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## #1 2006-03-23 03:03:46

DodgyPerson
Member
Registered: 2006-02-20
Posts: 3

### Re-Arraning!!!!

Ok i know it might be very simple for some people out here, but i am struggling with it:

I need to re-arrange the following formula in way so i can get Ns on its own!!!!

S = (Ns - N) / (Ns)

So as i said, i cant get Ns on its own!!!! WOuld be greatful if anyone could help!!!!

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## #2 2006-03-23 03:14:34

George,Y
Member
Registered: 2006-03-12
Posts: 1,306

### Re: Re-Arraning!!!!

(Ns - N) / (Ns)=Ns/Ns-N/(Ns)=1-1/s

As long as S=1-1/s, no matter what N is ,the equation S = (Ns - N) / (Ns)
is valid. That means N is Undetermined by this equation! (N can be any number)

another example a+2N=a+N+N, can you solve N out?

X'(y-Xβ)=0

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## #3 2006-03-23 03:15:31

ganesh
Moderator
Registered: 2005-06-28
Posts: 21,812

### Re: Re-Arraning!!!!

S = (Ns - N) / (Ns)

S(Ns)= Ns - N taking the denominator of the RHS to LHS

S(Ns) - Ns = -N (taking Ns to the LHS from RHS)

Ns - S(Ns) = N   (rearranging the terms to make N on the RHS positive)

Ns (1 - S) = N   (rearranging the LHS)

Therefore,

Ns = N / (1-S).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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