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#1 2006-03-17 17:09:25

NoSash
Member
Registered: 2006-02-06
Posts: 7

Vector Cross and Dot Product

See the image, show using the diagram...
I have no idea how to apply the diagram.

View Image: vector.jpg

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#2 2006-03-17 18:39:27

ganesh
Moderator
Registered: 2005-06-28
Posts: 13,902

Re: Vector Cross and Dot Product

This is called the scalar triple product. It is given by [a, b, c] where a, b, and c are the three vectors. You can understand this better if you know determinants. This can be of some help. And this one too.


Character is who you are when no one is looking.

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#3 2006-03-17 19:07:47

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Vector Cross and Dot Product

There are two ways to explain this.  Either geometrically or algebraically.

To do it algebraically, just do:

a = <a1, a2, a3>
b = <b1, b2, b3>
c = <c1, c2, c3>

And then compute each dot/cross product.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#4 2006-03-18 04:59:54

NoSash
Member
Registered: 2006-02-06
Posts: 7

Re: Vector Cross and Dot Product

Yes I know how to prove it algebraically... just not with the diagram.
I'm going to check out your links, thanks ganesh.

Last edited by NoSash (2006-03-18 05:00:19)

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#5 2006-03-22 11:19:47

NoSash
Member
Registered: 2006-02-06
Posts: 7

Re: Vector Cross and Dot Product

eh... if anyone is interested in the solution, here it is:

It's really simple actually... Because it is a CIRCLE, 2-dimensional shape, the scalar triple products are all equal to zero...
Three vectors in a 2D plane are always linearly dependent.

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#6 2006-03-22 15:50:17

fgarb
Member
Registered: 2006-03-03
Posts: 89

Re: Vector Cross and Dot Product

That's a very strange diagram. The equalities you wrote down are definitely true for the case where all three vectors are in the same plane as you said, but just to make sure you understand, these forumulas are also true for any three vectors.

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