AB is the diameter of a circle with center O.
C is a point on the circumference such that angle COB = θ
The area of the minor segment cut off by AC is equal to twice the area of the sector BOC.
θ is in degrees
Last edited by Agnishom (2014-02-02 00:50:06)
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I must have time to spare today; I'm looking through the unanswered posts; and I found this one. Did you ever do it?
Use the following:
area of a segment = area of the sector less the triangular bit.
And then you simplify this and use sin(A) = 2 sin(a/2).cos(a/2)
Takes a few lines only.
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei