Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**DaveRobinsonUK1****Member**- Registered: 2011-12-01
- Posts: 12

Hi All

I have come across this problem and it's giving me some jip.

I have a function

I would like to be able to put in the field of view and then solve for the focal length. Is this possible, what with

there being 2 internal variables?

Many thanks in advance.

David

I see it, but I don't believe it.

Offline

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

Not without knowing 'width' too.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,270

Hi;

You can solve for it but there will still be one more variable.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

Offline

Pages: **1**