I have come across this problem and it's giving me some jip.
I have a function
I would like to be able to put in the field of view and then solve for the focal length. Is this possible, what with
there being 2 internal variables?
Many thanks in advance.
I see it, but I don't believe it.
Not without knowing 'width' too.
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
You can solve for it but there will still be one more variable.
In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.