The cost of four items was $7.11 whether you added or multiplied the individual items. What was the cost of each item.
Our problem of the week for precalc. Problem is whether there is a set number of solutions. So help me out if you can please
Last edited by MajikWaffle (2006-03-13 18:30:02)
abcd = a+b+c+d = 7.11
We can also take advantage of the fact that (I assume) there are no items that have fractional cents.
a+b+c+d = 711
abcd = 711 × 10[sup]6[/sup]
And the prime factors of 711 × 10[sup]6[/sup] are 2[sup]6[/sup] × 3[sup]2[/sup] × 5[sup]6[/sup] × 79
Trial and error from here?
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I've heard of this problem before. All I did is used google and this is the page I got.
Majikwaffle, I think this solves your problem!
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