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#1 2006-03-09 13:33:13

kkkkk
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i need help with this math problem

3 eyed martians met with earthlings (each with 2 eyes) in the first ever intergalactic. observers noticed that there were only 14 people, yet there were 34 eyes. how many of the people are earthlings?

#2 2006-03-09 14:20:28

Ricky
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Re: i need help with this math problem

Here's the way I did it, a very non-matimatical way.

Let's assume that everyone is human.  Then there are 28 eyes.  For every human we replace with a martian, the net gain is 1 eye.

We need to gain 34-28 = 6 eyes, meaning there are 6 martians.  Thus, there are 8 humans.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

#3 2006-03-09 16:09:31

Dionysus
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Re: i need help with this math problem

Or you could do it the mathmatical way:

3x + 2y = 34        (3 eyes for each martian, 2 for each human, is equal to 34)
x + y = 14            (martians and humans combine to 14 people total)

we need to solve for y, ill choose the second equation and get:
y=-x + 14

Now substitue that in for y in the first equation and simplify:
3x + 2(-x + 14) = 34
3x - 2x + 28 = 34
x = 6

Now since X stands for martians, we know we have 6 martians, leaving us with 8 humans.
If you plug those in for the first equation you will find 3(6) + 2(8) = 34, thus there are:

6 Martians (18 eyes) and 8 (16 eyes) Humans.

Last edited by Dionysus (2006-03-09 16:10:25)

#4 2006-03-09 16:58:26

Ricky
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Re: i need help with this math problem

My way took about 5 seconds tongue

But I also had a feeling kkkkk didn't know how to solve systems of equations yet.  But I see no other mathimatical way to do it.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

#5 2006-03-09 17:48:38

ganesh
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Re: i need help with this math problem

3m+2e=34
m+e=14--->2m+2e=28
Therefore, m=6, e=8.
No. of maritans=6, no. of earthlings=8.
(Time taken = about 15 seconds)

This is how I teach my students to approach problems involving Simultaneous equations. Most examinations give about half a minute or less to solve such problems, and I think this is the best way it can be done!

dizzy roflol up


Character is who you are when no one is looking.

#6 2006-03-12 22:55:16

mathsyperson
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Re: i need help with this math problem

Ricky wrote:

Here's the way I did it, a very non-matimatical way.

Let's assume that everyone is human.  Then there are 28 eyes.  For every human we replace with a martian, the net gain is 1 eye.

We need to gain 34-28 = 6 eyes, meaning there are 6 martians.  Thus, there are 8 humans.

That's not very non-mathematical. It's logical at least, and logic fits in very micely with maths.
It's just a bit unconventional. It's how I'd have done it, though.


Why did the vector cross the road?
It wanted to be normal.

#7 2006-03-13 01:02:10

damathgirl
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Re: i need help with this math problem

I got 6 martians and 8 earthlings.

Everyone had 2 eyes at least so that would be 14*2=28 take 28 from 34 and you know that you need 6 martains to equal 34 eyes!?down or up      dunno

Last edited by damathgirl (2006-03-13 04:50:41)

#8 2006-03-13 07:22:45

MathsIsFun
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Re: i need help with this math problem

That works!


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

#9 2006-03-13 08:40:26

mikau
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Re: i need help with this math problem

Problems that involve martians are always funner.


A logarithm is just a misspelled algorithm.

#10 2006-03-13 08:52:07

ashwil
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Re: i need help with this math problem

I took the question literally:

14 people (humans) = 28 eyes
2 martians = 6 eyes

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