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#1 2014-03-09 07:51:51
- MERTICH
- Member
- Registered: 2013-12-01
- Posts: 18
Complex Numbers
If a and b are real numbers such that (a-ib)^2 =4,
verify that
a^4 +a^2 -16 =0
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#2 2014-03-09 12:52:10
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Complex Numbers
Hi MERTICH;
I do not think you can prove that because the statement is false.
so
a is obviously 2 and b is 0.
a is obviously -2 and b =0.
So a can be either -2 or 2 now just plug in.
2^4 +2^2 - 16 ≠ 0
(-2)^4 +(-2)^2 - 16 ≠ 0
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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