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Hello there, I just made this thread because I am too bored that we do not have anymore people who tell us that 0.999... ≠ 1. Since, I really want those days back,

0.999... ≠ 1

because I said so.

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

Do you want to give up the summation of a geometric series?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.** **A number by itself is useful, but it is far more useful to know how accurate or certain that number is.**

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I do not know. I just made this up because no one else was doing it

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

I would say the fact that there are no more posts like that is progress!

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.** **A number by itself is useful, but it is far more useful to know how accurate or certain that number is.**

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progress for whom?

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

The world and the forum.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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Why aren't there more closed threads and banned users?

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

Because there are not that many jerks on math forums.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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but they are basically good and fun to be around

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

Not really. They are abusive.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**anonimnystefy****Real Member**- From: Harlan's World
- Registered: 2011-05-23
- Posts: 16,015

The thing is that, fortunately, we do not get to see the ad hominem attacks, since most are moderated. What's left of their posts seems really funny, because they give themselves huge accomplishments.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

Yes, to the people responsible for the forum quality these guys are hardly funny or entertaining.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**anonimnystefy****Real Member**- From: Harlan's World
- Registered: 2011-05-23
- Posts: 16,015

I cannot begin to imagine it! Thanks for keeping the forum clean!

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

Hi;

Fortunately, the great majority are good.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,566

hi Agnishom,

I did say, in another thread, that I would try to give the Shilov proof that 0.9999recurring doesn't exist.

It has been a struggle for me and what follows may not be correct, so I'll apologise now.

Firstly, I couldn't read the small mathematical text on my Kindle. But the nice people at Kindle HQ suggested an app. that means I can read it on my laptop. That helped a lot.

But the relevant section is well on through the first chapter and you only want a small bit. So, could I condense, omit and edit in order to get to where you want? Here's my attempt:

Let r = 0.99999 recurring.

r ∈ [0.9,1) That is r lies in the half open region bounded by 0.9 and 1 but is strictly less than 1.

Similarly, r ∈ [0.99,1) and r ∈ [0.999,1) etc.

So r is in the intersection of all these regions.

But it is a property of the real numbers that, for any two reals, a and b, you can always find a value between them.

So the half open regions cannot have a non empty intersection.

Therefore, r cannot exist.

You may not like this, but it seems to be a requirement for a consistent real number theory. And it is not without precedent. He has already, earlier, shown that 0 has no multiplicative inverse, which is why you mustn't divide by zero.

I think that's it. I don't claim that's how he puts it nor that I like it but there you are. You could always read the book yourself.

Meanwhile, if he is right, then it follows that any discussion of r is meaningless.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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bob bundy wrote:

Let r = 0.99999 recurring.

r ∈ [0.9,1) That is r lies in the half open region bounded by 0.9 and 1 but is strictly less than 1.

Similarly, r ∈ [0.99,1) and r ∈ [0.999,1) etc.

So r is in the intersection of all these regions.

But it is a property of the real numbers that, for any two reals, a and b, you can always find a value between them.

So the half open regions cannot have a non empty intersection.

Therefore, r cannot exist.

This is actually a proof by contradiction that *r* ≥ 1. In other words the assumption that *r* < 1 leads to the absurdity that *r* does not exist.

By the exact same method, you can prove by contradiction that *r* > 1 is also impossible.

Suppose *r* > 1. Then *r* ∈ (1, 1.1], *r* ∈ (1, 1.01], *r* ∈ (1, 1.001],
and by the same argument it will be found that *r* does not exist.

Conclusion: If *r* exists, then *r* = 1.

*Last edited by Nehushtan (2014-02-12 01:22:06)*

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**TheTick****Member**- Registered: 2012-12-03
- Posts: 27

What is .99999 recurring + .33333 recurring if .99999 recurring does not equal 1?

Edit- I have no idea btw...

*Last edited by TheTick (2014-03-12 15:38:38)*

Spooooon!!!

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'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,566

Interesting link, thanks.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

The American way?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,203

I agree wholeheartedly.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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