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#1 2014-02-09 15:34:05

Full Member


angles in a circle

In triangle ABC, AB = 5, AC = 4, and BC = 3. Let P be the point on the circumcircle of triangle ABC so that \angle PCA = 45^\circ. Find CP.
This is pretty hard. I got to where AB is a diameter (ACB is 90 degrees)  and the radius is 2.5, but what next?
thanks! big_smile

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#2 2014-02-09 20:58:24

bob bundy


Re: angles in a circle

hi thedarktiger,

The following method will work but I'll keep looking for a quicker way.

You're right about AB being a diameter so I've marked the centre as O, and there are lots of radii that must therefore be 2.5 long.

In my diagram I have also marked the midpoints of AC as D and of PC as E.

Triangles OAC and separately POC, are isosceles and the lines from O to those midpoints will cut each isosceles triangle down the middle.  That means there will be a right angled triangle in each half.

Now lots of trigonometry.

Use acos(2/2.5) to get angle OCD and hence calculate angle OCE.

Now you can use that to calculate EC and double this to get PC.


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Last edited by bob bundy (2014-02-09 21:08:57)

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