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**thedarktiger****Member**- Registered: 2014-01-10
- Posts: 65

In hexagon ABCDEF, AB = DE = 2, BC = EF = 4, CD = FA = 6, and all the interior angles are equal. Find the area of hexagon ABCDEF.

I cannot find any theorems or anything for that area...please explain...AND THX

Good. You can read.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,269

hi

Don't know if this is the quickest way but it should work.

Box in the hexagon as shown in my diagram. (All the angles are 120)

Use trig to calculate the length and width of the box.

Calculate its area and subtract the areas of the unwanted triangles.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,247

Hi;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**thedarktiger****Member**- Registered: 2014-01-10
- Posts: 65

Thanks guys! actually you don't have use trig, the triangles are 30-60-90, so sides are 2:1:sqrt(3)

Thanks a ton! wouldn't have got without ya!

I got that too bobbym.

*Last edited by thedarktiger (2014-01-11 22:30:02)*

Good. You can read.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,247

Hi;

Very good! Well done.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,269

thedarktiger wrote:

you don't have use trig, the triangles are 30-60-90, so sides are 2:1:sqrt(3)

Hhhmmm. And where did that result come from, I wonder?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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