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You are not logged in. #1 20140105 06:15:59
Proof verification for neighbor fractions*If I turn out to have a wrong answer, please no hints or showing an valid proof. I want to do it on my own ! #2 20140105 20:42:01
Re: Proof verification for neighbor fractionshi Alallo Now, reduce the common numbers : We must now prove that the left hand side has irreductible fractions. Lets see what would happen if these fraction were reductible. let Reduce and multiply by Ln: *************** But We have considered the initial fractions to be reductible and have arrived at a false result. An integer cannot be equal to (+1/z*p) So, the initial fractions must be irreductible. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #3 20140109 02:56:29
Re: Proof verification for neighbor fractionsThe reason why the left hand side cannot be equal to the right hand side is because we have considered our variables (a=zy,etc.) to be integer whose factorization were also integers.(We are dealing with fractions, this is the reason why we need them to be integers.) So, when we arive at this result : ynlm(not equal to) +1/zp, the left hand side is a substraction of integers. But the right hand side is a fraction with 1/zp(zp also being integers). So, the result shall be inferior to 1. The only exception where it won't be inferior is the case were the leftright hand side shall be equal to +1. #4 20140109 03:01:48
Re: Proof verification for neighbor fractionsBy the way, I forgot to treat the case where there might exist one fraction which is factorizable and the other not. Last edited by AlAllo (20140109 03:06:48) #5 20140109 03:15:12
Re: Proof verification for neighbor fractionsExplanation in post 3 is what I was seeking. Last edited by bob bundy (20140109 03:15:57) You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #6 20140109 03:18:19
Re: Proof verification for neighbor fractionsOh I really need to put it in the numerator and show it ? I didn't know that ! #7 20140109 03:20:31
Re: Proof verification for neighbor fractionsBy the way, am I right by saying that the exception (the equality with 1 or 1) is telling us that such factorization exists? Last edited by AlAllo (20140109 04:31:29) #8 20140109 03:44:33
Re: Proof verification for neighbor fractionsOk, yeah, I think that's it : Last edited by AlAllo (20140109 04:48:27) #9 20140109 20:28:52
Re: Proof verification for neighbor fractions
How many steps to put in is not a fixed thing. You have to demonstrate that your proof is rigorous. If there's marks in it, I would 'err' on the side of caution and put in too many rather than too few. No one can complain at that. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei 