Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #3 20131219 00:55:05
Re: Squeeze TheoremUse the fact that sin(e^{x}) ≤ 1 and play with the inequality until you can bound your function. #5 20131219 01:11:44
Re: Squeeze TheoremThe sine function, regardless of the argument (and as long as it is real), is always at least bounded between 1 and 1. Do you see what we are trying to do? #7 20131219 01:44:24
Re: Squeeze TheoremYes, that is correct. The limit of the left and right bound are easy to get, so you should be able to get the original limit now. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #8 20131219 02:08:23
Re: Squeeze TheoremYes (with the square root signs). 