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#1 2006-02-28 17:10:39

kynetikg01
Member
Registered: 2006-01-24
Posts: 3

derivatives

hello everyone. i was doin some calculus and got stuck on this problem
f(x)= 10 - x

find the : f^(-1)(x)= ?

written as f'(x) just replace the ' w/ the -1

what does that mean? is that the inverse or somethIN?
i've been dealing w/ derivatives
-thanks

Last edited by kynetikg01 (2006-02-28 17:12:13)

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#2 2006-02-28 17:56:56

naturewild
Member
Registered: 2005-12-04
Posts: 30

Re: derivatives

I'm positive that it's asking for an inverse. But I dont know why you are dealing with inverse when you have learnt derivatives.

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#3 2006-02-28 18:06:14

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,908

Re: derivatives

Ya it's inverse function.
Write it like this:
y=10-x
-x=y-10
x=10-y
This is the inverse function:
f^(-1)(y)=10-y
[corrected]

Last edited by krassi_holmz (2006-03-01 04:30:18)


IPBLE:  Increasing Performance By Lowering Expectations.

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#4 2006-03-01 04:15:17

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: derivatives

I think there's a mistake in there.

y = 10-x
x+y = 10
x = 10-y

Therefore, f[sup]-1[/sup](x) = 10-x.


Why did the vector cross the road?
It wanted to be normal.

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#5 2006-03-01 04:28:58

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,908

Re: derivatives

Mathsy's right.


IPBLE:  Increasing Performance By Lowering Expectations.

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#6 2006-03-01 04:30:37

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,908

Re: derivatives

[corrected]


IPBLE:  Increasing Performance By Lowering Expectations.

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