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## #1 2013-12-12 05:35:47

evinda
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### Wronskian use identities !

Hello!!!
Could you help me at the following exercise?
Let

,
solutions of the differential equation y''+ay'+by=0  (a and b real constants) so that
is not constant.If
any solution of the differential equation ,use the identities of the Wronskian to show that there are constants
,
so that:
, d_{1}v_{1}'(0)+d_{2}v_{2}'(0)=f'(0)
and that each solution of the differential equation has the form:
.

Last edited by evinda (2013-12-12 05:37:39)

## #2 2013-12-12 08:02:05

bobbym

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### Re: Wronskian use identities !

Hi;

The Wronskian is

I do not see how to use v1 and v2?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #3 2013-12-12 08:09:27

anonimnystefy
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### Re: Wronskian use identities !

Hi

I think evinda is referring to this:Wronskian.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #4 2013-12-12 08:15:28

bobbym

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### Re: Wronskian use identities !

I used the one in Mathematica, they should be the same thing.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #5 2013-12-12 08:24:04

evinda
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### Re: Wronskian use identities !

The Wronskian is
|u(0)     v(0)|
|u'(0)    v'(0) |
But...how can I show that  there are constants

,
so that:
, d_{1}v_{1}'(0)+d_{2}v_{2}'(0)=f'(0) ??

Last edited by evinda (2013-12-12 08:27:13)

## #6 2013-12-12 08:29:21

bobbym

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### Re: Wronskian use identities !

What functions are u and v? They are not defined.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #7 2013-12-12 08:36:10

anonimnystefy
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### Re: Wronskian use identities !

Well, here they are called v1 and v2 instead of u and v. Does not change much.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #8 2013-12-12 08:38:25

bobbym

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### Re: Wronskian use identities !

What is v1 and v2?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #9 2013-12-12 08:39:47

anonimnystefy
Real Member

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### Re: Wronskian use identities !

They are two solutions of the differential equation for which it's true that v1/v2 is not constant.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #10 2013-12-12 08:41:45

bobbym

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### Re: Wronskian use identities !

That would require solving the DE. Since when do you need the solve the DE to get the Wronskian?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #11 2013-12-12 08:43:48

evinda
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### Re: Wronskian use identities !

#### anonimnystefy wrote:

They are two solutions of the differential equation for which it's true that v1/v2 is not constant.

Exactly!!The Wronskian is:
| v1(0)    v2(0)  |
| v1'(0)  v2'(0)  |

## #12 2013-12-12 08:45:01

evinda
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### Re: Wronskian use identities !

#### bobbym wrote:

That would require solving the DE. Since when do you need the solve the DE to get the Wronskian?

Which DE do you mean that I have to solve??

## #13 2013-12-12 08:51:08

bobbym

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### Re: Wronskian use identities !

When I solve the DE, I get an answer that has to arbitrary constants s1 and c2

I can not eliminate them without some more information.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #14 2013-12-12 08:53:52

evinda
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### Re: Wronskian use identities !

#### bobbym wrote:

That yields a Wronskian of

Now what?

I haven't understood..Do you mean that I have to take the derivative of the Wronskian and solve the DE or which DE do you mean??

## #15 2013-12-12 08:56:45

bobbym

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### Re: Wronskian use identities !

This DE, y''+ay'+by=0

If v1 and v2 are solutions of that DE then you have to solve the DE to get the solutions. I have already done that.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #16 2013-12-12 09:08:36

evinda
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### Re: Wronskian use identities !

I found the Characteristic equation,that is

that has discriminant
with

So,

Am I right so far?And how can I continue?

Last edited by evinda (2013-12-12 09:10:12)

## #17 2013-12-12 09:10:12

bobbym

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### Re: Wronskian use identities !

I am not getting that as a solution to the DE. Where is c1 and c2 in your solution?

Did you copy the question correctly?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #18 2013-12-12 09:11:47

anonimnystefy
Real Member

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### Re: Wronskian use identities !

Hi evinda

Those are the solutions, but I don't think you are supposed to use them.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #19 2013-12-12 09:12:59

bobbym

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### Re: Wronskian use identities !

Shouldn't you have use the roots rather than the discriminant?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #20 2013-12-12 09:13:43

evinda
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### Re: Wronskian use identities !

#### bobbym wrote:

I am not getting that as a solution to the DE. Where is c1 and c2 in your solution?

Did you copy the question correctly?

Yes,I copied the question correcty..Should I have used

and
instead of c_{1}  and
?

Last edited by evinda (2013-12-12 09:14:50)

## #21 2013-12-12 09:15:22

evinda
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### Re: Wronskian use identities !

#### anonimnystefy wrote:

Hi evinda

Those are the solutions, but I don't think you are supposed to use them.

But???How else can I start???

## #22 2013-12-12 09:17:13

evinda
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### Re: Wronskian use identities !

#### bobbym wrote:

Shouldn't you have use the roots rather than the discriminant?

Where do you mean?At the general solution?

## #23 2013-12-12 09:17:15

bobbym

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### Re: Wronskian use identities !

This is what I am getting for a solution to that DE:

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #24 2013-12-12 09:19:15

anonimnystefy
Real Member

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### Re: Wronskian use identities !

#### evinda wrote:

I found the Characteristic equation,that is

that has discriminant
with

So,

Am I right so far?And how can I continue?

So is she.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #25 2013-12-12 09:21:03

evinda
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### Re: Wronskian use identities !

And how can I continue now??