Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #526 20131205 18:15:32
Re: SeriesI don't mind having the discussion. "Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense"  Buddha? "Data! Data! Data!" he cried impatiently. "I can't make bricks without clay." #527 20131205 21:09:13
Re: SeriesThanks gAr.
I am sure I showed it to you already. I know we discussed it. It is also useless for this sequence. I used Romberg and it worked well. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #528 20131205 22:08:24
Re: SeriesYes. Is it the one with all the square roots and stuff? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #529 20131205 22:14:41
Re: SeriesCode:accelerate[n_]:=Module[{d,b,c,s}, d=(3+Sqrt[8])^n; d=(d+1/d)/2; b=1; c=d; s=0; Table[c=bc;s=s+c*a[k];b=(k+n)(kn) b/((k+1/2)(k+1)),{k,0,n1}]; s/d] Remember how to use it? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #530 20131206 00:20:57
Re: SeriesThat's the one I was thinking of. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #531 20131206 00:24:05
Re: SeriesI am pretty sure it is just for alternating sequences. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #532 20131206 00:27:34
Re: SeriesYes, I know. It also has to start at 0. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #533 20131206 00:31:01
Re: SeriesYou can adjust the index to handle that. Anyways it is not useful on this problem. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #534 20131212 09:55:31
Re: SeriesHi bobbym Last edited by anonimnystefy (20131212 09:57:23) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #535 20131212 10:17:58
Re: SeriesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #536 20131212 10:22:21
Re: SeriesHm, isn't romberg for integrals? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #537 20131212 10:25:46
Re: SeriesIt is for sequences that are the result of numerical integrations on an integral. Actually it is a bunch of sequence accelerators. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 