Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

## #1 2006-02-27 12:56:36

x1000uf
Novice

Offline

### help me!! y-y1=m(x-x1)

i dont know how to do it with factions someone help??!!!!

im gonna fail becuase i dont know how to do it

y-9=2/5(x+20

## #2 2006-02-27 18:18:08

MathsIsFun

Offline

### Re: help me!! y-y1=m(x-x1)

What was the actual question? How to simplify y-9=2/5(x+20 ) ?

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

## #3 2006-02-27 18:24:56

ganesh
Moderator

Offline

### Re: help me!! y-y1=m(x-x1)

I guess the question is finding the equation of a straight line whose slope is 2/5 and which passes through the point (-20, 9).

The equation of a straight line passing through a given point (x1, y1) and with a given slope, m, is

y - y1 = m(x - x1).

In the given problem, x1 = -20, y1=9 and m=2/5.
Therefore, the equation of the straight line is

y-9 = 2/5[(x+20)]
5y-45 = 2x + 40
5y - 2x = 85
2x - 5y + 85 = 0 is the required equation.

Character is who you are when no one is looking.

## #4 2006-02-27 20:07:14

krassi_holmz
Real Member

Offline

### Re: help me!! y-y1=m(x-x1)

or y=(2x+85)/5?

IPBLE:  Increasing Performance By Lowering Expectations.