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#1 2013-10-24 21:32:18

mukesh
Member
Registered: 2010-07-18
Posts: 30

Arithmetic Means

show that the sum of the arithmetic means between two given quantities ,equidistant from the beginning and the end is constant.

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#2 2013-10-24 22:32:13

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,257

Re: Arithmetic Means

hi mukesh

I am not very clear about what is variable and what fixed here.  Let's see if I can sort this out.

Let beginning = b
end = e

first quantity = a
second quantity = c

equidistant => a - b  = e - c

=> a + c = e + b

So, if e and b are fixed it should be easy for you to finish this off.  smile

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#3 2013-10-25 04:50:10

mukesh
Member
Registered: 2010-07-18
Posts: 30

Re: Arithmetic Means

sir here beginning and last numbers are constant,fixed.
plse explane in brief ,i m in trouble

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#4 2013-10-25 19:29:27

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,257

Re: Arithmetic Means

That's what I was assuming.

b + e = constant => a+ c is constant.

All you need to fill in is the arithmetic mean.  Do you know what that is?

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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