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•  » Did I simplify these sqareroot problems right??? I sure hope so!

## #1 2006-02-22 15:38:56

4littlepiggiesmom
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### Did I simplify these sqareroot problems right??? I sure hope so!

1. sqrt 7 8 sqrt 18/sqrt 2= I got 3sqrt 7

2. sqrt 10 8 sqrt16/sqrt5 = I got 4sqrt2

And the last one38sqrt 8/64= I got 3sqrt3/4

## #2 2006-02-22 15:55:49

mikau
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### Re: Did I simplify these sqareroot problems right??? I sure hope so!

First. In 1. Do you mean sqrt(7) 8 sqrt(18)/sqrt(2) ??? In this case, I got sqrt(7) * 8*3 or 24 sqrt(7). I think you forgot the 8 coefficient in front of the radical.

Just remember these are the rules. sqrt(m) * sqrt (n) = sqrt (mn). Also sqrt (5/3) = sqrt (5)/ sqrt(3) also you can always multiply the numerator and denominator of a fraction by the same quanity without changing the value.

A logarithm is just a misspelled algorithm.

## #3 2006-02-22 16:02:18

ganesh
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### Re: Did I simplify these sqareroot problems right??? I sure hope so!

(1) √ 7*8*√ 18/√ 2 = 24*√ 7

(2) √ 10*8*√16/√5= 32*√2

Character is who you are when no one is looking.

## #4 2006-02-22 16:26:36

4littlepiggiesmom
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### Re: Did I simplify these sqareroot problems right??? I sure hope so!

No my 8 should be  * for the multiplication sign??? It's been a long night of checking over homework with lots of english to go??? Sorry

1 should be the square root of 7 times(*) the square rot of 18 over the square root of 2?

2. the square root of 10 times(*) the square root of 16 all over(divided by) the square root of 5

Sorry for the mix up

## #5 2006-02-23 06:10:22

John E. Franklin
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### Re: Did I simplify these sqareroot problems right??? I sure hope so!

So you are right mom on 1 and 2 because they got exactly 8 times your answers!
But your 3rd last one: 38sqrt 8/64= You said you got 3sqrt3/4, please explain youself.

Last edited by John E. Franklin (2006-02-23 06:11:23)

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