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You are not logged in. #1 20130910 02:34:08
Relation, Solution Set, GraphHi, #2 20130910 04:49:37
Re: Relation, Solution Set, Graphhi atran You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #4 20130911 01:37:20
Re: Relation, Solution Set, GraphIf an equation has only one unknown and some solutions (n of them) then you could put these solutions in a list and make it an ntuple. Strictly, that's a single ntuple, not a set of them. A function isn't an equation so it doesn't have a solution set. See http://en.wikipedia.org/wiki/Graph_of_a_function Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #5 20130911 05:41:22
Re: Relation, Solution Set, GraphThanks for your response. #6 20130911 16:56:33
Re: Relation, Solution Set, GraphYes. To be clear you need to understand the difference between domain, codomain and range. I was asked that here: You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #7 20130912 04:56:47
Re: Relation, Solution Set, GraphSay I have y=x²1, where x belongs to the real set, and y to negative integers. Obviously, the graph consists only of one point, which is (0, 1). #8 20130912 17:28:20
Re: Relation, Solution Set, Graphhi atran
So you have answered your own question. The domain is {reals} and the codomain is {negative integers}
Now that is more tricky to answer. I think it depends on exactly what you mean by 'the same graph'. This is a many : many relationship as every x has two ys and every y has two xs (or none if you pick points beyond 5) If the domain and codomain are 5 ≤ x , y ≤ +5 and secondly 10 ≤ x , y ≤ +10 then the graphs are the same and the domain/codomain can have different sets. But what about 2 ≤ x , y ≤ +5 ? Now only part of the circle is visible in the graph so the same relationship gives different graphs. It seems to me that relationships must be properly defined in the same way as functions, so that would require the domain and codomain are part of the definition . That would make the answer to your question 'No'. (I think .... ) Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #9 20130912 20:31:57
Re: Relation, Solution Set, GraphHi Bob, Last edited by atran (20130912 22:32:22) #10 20130912 22:35:38
Re: Relation, Solution Set, Graphhi atran You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei 