Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20130724 08:31:09
swap last and first digitHi, #2 20130724 11:07:34
Re: swap last and first digitHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20130907 04:37:26
Re: swap last and first digitDoesn't this violate the rules: Last edited by Trenin (20130907 04:37:44) #4 20130907 05:23:19
Re: swap last and first digitHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20130907 06:24:56
Re: swap last and first digitHi bobbym The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #6 20130907 06:30:18
Re: swap last and first digitYes, I do. I just wrote the subroutine for the 30th time. This time I will keep it. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #7 20130907 06:39:01
Re: swap last and first digitJust the switching code. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #8 20130907 06:43:50
Re: swap last and first digitCode:Use 12345 as an example. h = t = IntegerDigits[12345] h[[1]] = t[[Length[t]]]; h[[Length[t]]] = t[[1]]; If you enter h you will output {5,2,3,4,1} In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 