By mathimatical law, you can only say QED when you start out with "Pf" or "Proof".  But we'll let you go with a warning this time.

On k + 89, I was below with this 3 times correction still by factor of 1.062801932.
So with the new correction factor, it's kind of dumb, but, you'll laugh, but...
percentage that it was from machine B knowing first that the piece is
defective = 35% ((4 x 3)/(5 + 4 + 2)) * correction factor, where correction factor = (5 + 4 + 2)/(3*(.35 x 4 + .25 x 5 + .40 x 2))

Solution to Problem # k + 97

After 8 hours, the first man has walked (8x4) kilometers, i.e. 32 kilometers.
After 8 hours, the second man has walked (1+2+3+4+5+6+7+8) kilometers, i.e. 36 kilometers. In the ninth hour, the first man is walking at 4 km/hr and the second is walking at 9 km/hr. Let them meet after time t hours. 
Hence, 4t+9t=4, 13t=4, t=4/13 hours = 18.46 minutes approximately.
Hence, they would meet after 8 hours and 18.46 minutes approximately.

mathsyperson is correct

lol. You love this instantaneous velocity.  I stand by my k+97 solution(s).  There was nothing in the question that required the solution agreed upon.  Distance travelled does not prove constant velocity during a time period.  I have yet to see an instance of infinite acceleration either.  My equations describe the motion of both people as correctly as your assumptions.

  I am not trying to dispute your solution, just pointing out that the wording of a problem is just as vitally important as the mathematics that lead to a solution.  Your solution and mine are equally valid given the way in which it was worded.  More details would be needed to invalidate either one.
 
  My answers are more correct though!  Just kidding.  Why quibble over less than 30 seconds?

Last edited by irspow (2006-02-22 02:42:33)

Thanks for the concession. lol.  Interesting how both are correct and yet different with a problem stated as such, no?

I love that kind of problems.

You're right, irspow, it would be more natural to model the man as having a constant acceleration like that, but ganesh did say that the men were moving towards each other, so the second part of your k+97 solution was not needed.

Problem # k +

From 3 men and 4 women, three persons are to be selected
in such a way that at least one woman is selected. In how many
different ways can they be selected?

Ricky, try again!

Problem # k + 101

Prove that n! + 1 is composite for infinitely many values of n where n is a positive integer.

After a long time, here's solution to Problem # k + 42

Problem # k + 42

On a deserted island live five people and a monkey. One day everybody gathers coconuts and puts them together in a community pile, to be divided the next day. During the night one person decides to take his share himself. He divides the coconuts into five equal piles, with one coconut left over. He gives the extra coconut to the monkey, hides his pile, and puts the other four piles back into a single pile. The other four islanders then do the same thing, one at a time, each giving one coconut to the monkey to make the piles divide equally. What is the smallest possible number of coconuts in the original pile?

The smallest solution is 3121 coconuts in the pile.