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**CadeStaker****Member**- Registered: 2013-08-22
- Posts: 2

**Thank you so much for visiting this thread.** I recently started my freshman year of college with Math 1010 (intermediate algebra). So far it has been fairly easy and just a review of things, but the final **two questions** on one of my tests had me completely stumped, and left me** in need of an explanation and answer (detailed if your time permits)**;

First Question:

2(t - 2) - 3(3t - 1) = 8 - 5(5t + 4)

Second Question:

-2(a - 2) - [3 - 2 (4a - 1)]

I am not that great at using the Distributive Property on equations with more than 3 terms. I can perform (below) easily.

2 (t - 4)

2(t) + 2(-4)

But not (below)

2(9 - 5 [-4x - 3])

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

Welcome to the forum. I am assuming you want to solve for t?

Expand it out.

Add 1 to both sides.

Add 7t to both sides.

Add 11 to both sides.

Divide both sides by -18.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**CadeStaker****Member**- Registered: 2013-08-22
- Posts: 2

bobbym wrote:

Hi;

Welcome to the forum. I am assuming you want to solve for t?

Expand it out.

Add 1 to both sides.

Add 7t to both sides.

Add 11 to both sides.

Divide both sides by -18.

Thank you very much. In your first step, of expanding it out, could you give me your step-by-step equations, with the distributive property as well? I would really appreciate it, as I have always had issues with the distributive property.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

I did not use the distributive property. I used multiplication and simplification.

The second question is not an equation, there is no equal sign. What do you want to do with it.?

It can be simplified to look like this,

6a - 1

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,544

You did use the distributive property in expanding the brackets.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Not really.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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