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#1 2013-08-15 03:57:24

maths4prasad
Member
Registered: 2013-08-15
Posts: 3

n th derivative

the problem is to prove that -∫(-1 to 1) u^(n-1)(x) u^(n+1)(x)dx = (-1)^n ∫(-1 to 1)u(x)u^(2n)(x)dx
here (n-1),(n+1),(2n) are n th derivatives and u(x) = (x²-1)^n
plz help me to prove above problem...

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#2 2013-08-15 04:29:11

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,663

Re: n th derivative

Hi;

You should latex these so they are readable.

This is a good online latex creator. It uses pull down menus and produces perfect latex every time.

http://latex.codecogs.com/editor.php

That is the LHS of your question. Refresh my memory, which polynomials are u(x)?


In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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#3 2013-08-21 04:43:01

maths4prasad
Member
Registered: 2013-08-15
Posts: 3

Re: n th derivative

thanks for replying..
that problem u interpreted is correct, and u(x)=\left(x^2-1)^n

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#4 2013-08-21 07:27:53

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,663

Re: n th derivative

Hi;

So the whole question looks like this:


In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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