Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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You are not logged in. #401 2006-02-16 11:53:51
Re: Problems and SolutionsI think my and irspow's methods are pretty much the same, just worded differently. We get the same answer, anyway. Why did the vector cross the road? It wanted to be normal. #402 2006-02-16 12:04:42
Re: Problems and SolutionsSorry, I didn't mean to jump in your spot. The wording of this problem is what had me scratching though. I wasn't sure if ganesh wanted the over-all probability of drawing a defective bolt from B or the probability that I (or should I say we?) calculated. #403 2006-02-16 12:54:23
Re: Problems and SolutionsDon't worry, you're in your own spot. Our spots just happen to look similar. Why did the vector cross the road? It wanted to be normal. #404 2006-02-16 23:21:55
Re: Problems and SolutionsBoth mathsyperson and irspow are correct. Well done. Character is who you are when no one is looking. #405 2006-02-17 04:03:04
Re: Problems and Solutionsk+90's formula is: Anybody want to try their hand at an induction proof, or should I? "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #406 2006-02-17 15:32:01
Re: Problems and SolutionsRicky is correct. I shall wait for someone to post a proof. Character is who you are when no one is looking. #407 2006-02-17 15:51:11
Re: Problems and SolutionsProblem # k + 91 Character is who you are when no one is looking. #408 2006-02-17 23:11:28
Re: Problems and Solutions
Why did the vector cross the road? It wanted to be normal. #409 2006-02-17 23:36:45
Re: Problems and Solutionsmathsyperson's solution to problem # k + 91 is correct. I shall post the method if none of the others are able to give a proper solution with the steps. Character is who you are when no one is looking. #410 2006-02-18 07:21:57
Re: Problems and Solutions
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #411 2006-02-18 10:17:34#412 2006-02-18 19:47:57
Re: Problems and SolutionsRicky and irspow are correct! Character is who you are when no one is looking. #413 2006-02-18 20:35:43
Re: Problems and SolutionsProblem # k + 93 Character is who you are when no one is looking. #414 2006-02-19 00:48:50
Re: Problems and Solutions
Why did the vector cross the road? It wanted to be normal. #415 2006-02-19 01:33:13
Re: Problems and SolutionsWell done, mathsyperson! Character is who you are when no one is looking. #416 2006-02-19 02:06:10
Re: Problems and SolutionsNice job, Mathsyperson! I spent like twenty minutes to come up with the same answer using the disk method of integration. #417 2006-02-19 04:00:24
Re: Problems and SolutionsThis is not my type of problem, but here goes nothing. Last edited by irspow (2006-02-20 00:14:16) #418 2006-02-19 18:13:54
Re: Problems and Solutionsirspow, please check the solution you posted again Character is who you are when no one is looking. #419 2006-02-19 18:36:18
Re: Problems and SolutionsProblem # k + 95 Character is who you are when no one is looking. #420 2006-02-19 21:07:26
Re: Problems and SolutionsSo a=-c or a=-b and Last edited by krassi_holmz (2006-02-19 21:26:54) IPBLE: Increasing Performance By Lowering Expectations. #421 2006-02-19 21:31:02
Re: Problems and Solutionsk+95: IPBLE: Increasing Performance By Lowering Expectations. #422 2006-02-20 00:22:20#423 2006-02-20 01:24:03
Re: Problems and SolutionsYeah IPBLE: Increasing Performance By Lowering Expectations. #424 2006-02-20 01:25:03
Re: Problems and Solutions
Character is who you are when no one is looking. #425 2006-02-20 02:48:19
Re: Problems and SolutionsProblem # k + 96 Character is who you are when no one is looking. |