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#26 2013-07-13 04:16:59

TryingMyBest50
Member
Registered: 2013-07-12
Posts: 13

Re: Linear equations

So i would solve the linear inequality problem the same way i solve the linear equation, but replace the equal sign with < or >

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#27 2013-07-13 04:24:49

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Linear equations

Hi;

There is no reason to replace the equality with either of those that I understand. It is totally arbitrary.

Is there more to the question? Have you left anything out?


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#28 2013-07-13 04:44:27

TryingMyBest50
Member
Registered: 2013-07-12
Posts: 13

Re: Linear equations

No, i just need to change my 1-variable linear equation to a linear inequality using < or >.

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#29 2013-07-13 04:54:23

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Linear equations

Post #25 does that for all 4 possibilities.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#30 2013-07-15 02:07:46

TryingMyBest50
Member
Registered: 2013-07-12
Posts: 13

Re: Linear equations

Good morning bobbym. Would i solve it like this

4x + 11 < 6x - 3

4x - 6x + 11 < - 6x - 6x - 3

2x + 11 -11 < -3 - 11

2x < - 8

-2x/-2 < -8/-2 = x < 4

and check it

4(4) + 11 < 6(4) - 3

16 + 11 < 24 - 3

27 < 27

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#31 2013-07-15 02:17:30

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Linear equations

Hi;

I am not getting that. Please recheck your work.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#32 2013-07-15 02:29:39

TryingMyBest50
Member
Registered: 2013-07-12
Posts: 13

Re: Linear equations

Ok, if you had to change 4x+11=6x-3 into a linear inequality how would you do it, and how would you solve it?

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#33 2013-07-15 02:32:29

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Linear equations

Hi;

In line 2) 4x - 6x = -2x

In your line 3) -3 - 11 = -14

Here is how to do it.

4x + 11 < 6x - 3

Take 4x away from both sides.

11 < 2x - 3

Add 3 to both sides.

14 < 2x

Divide both sides by 2.

7 < x

Or

x > 7


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#34 2013-07-15 02:54:29

TryingMyBest50
Member
Registered: 2013-07-12
Posts: 13

Re: Linear equations

Ok, i see that i should've have added the 3 - 11. Thank you so much!:) Have a great morning!

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#35 2013-07-15 03:00:25

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Linear equations

You are welcome, post if you need more.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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