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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

Hello Forum, after i find the solution to this equation 5m+10=8m-2, how do i check to make sure the answer is correct. Greatly appreciate any help!

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Hi TryingMyBest50;

Welcome to the forum.

Subtract 5m from both sides.

Add 2 to both sides.

Divide both sides by 3.

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

Hi bobbym, i first need to say that math is not my subject. With that said, is that how i check that the solution is a true statement?

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,664

hi TryingMyBest50

Welcome to the forum.

And then check by working out if 5x4 + 10 gives the same result as 8x4 -2

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

You check by substituting the 4 into the m.

5 x 4 = 20 and 8 x 4 = 32

20 + 10 = 30 and 32 - 2 = 30

Checked and you are done.

**In mathematics, you don't understand things. You just get used to them.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,664

hi bobbym

how are you today?

That latex error was strange. \times (4) worked for me in a preview.

Test

curious

Maybe it's all in the spaces?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Hi Bob;

I am fine, how is everything?

Until it gets into the cache, some latex will not work. It is functioning okay now.

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

Hi bob, i want to thank both you and bobbym for your feed back. So i just replace the answer with what ever letter is presented to check my that the sollution is correct, right?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Replace the letter ( variable ) that you solved for and do the arithmetic correctly. Both sides should be the same.

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

Variable, i knew the letter had a name i just coudln't think of it. Thank you so much for your help! You guy's are great! Have a Blessed day!

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

You are welcome.

**In mathematics, you don't understand things. You just get used to them.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,664

hi bobbym,

While your latex was producing an error I copied it so I could check the ascii codes of your symbols. Then when that revealed nothing I did my test post 6. And your original latex is still there producing an error. So I don't think it's a cache problem.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Hi Bob;

On mine it is working fine. Does it look like this for you?

**In mathematics, you don't understand things. You just get used to them.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,664

hi bobbym,

Yes, it does.

But look at post 6

Bob

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Hi;

Sorry, I did not see that.

Removing the spaces causes it to work.

**In mathematics, you don't understand things. You just get used to them.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,664

Oh yes. But this is still weird for me:

Wont work version: 5 \times (4)+10 = 8 \times (4)-2

De-spaced version works: 5 \times (4)+10=8 \times (4)-2

But my working version had loads of spaces:

5 \times (4) + 10 = 8 \times (4) -2

Just got to put my head in some ice. Back later.

Bob

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

That is true. I can remove one space and everything is fine.

Just got to put my head in some ice.

Sounds cooling!

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

Hi guy's it's me again. How do i turn this linear equation 4x+11=6x-3 into an linear inequality? Would i write it like 4x<+11=6x<-2, and the lesser sign is underlined?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Hi;

I have never heard of that...

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

Hi Bobbym, I need to change the linear equation 4x+11=6x-3 into a linear inequality (using < or >). Can it be done?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Why couldn't you just replace the = with a < or a >?

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

ok, so how would you solve the equation using < or >.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

Which one?

**In mathematics, you don't understand things. You just get used to them.**

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**TryingMyBest50****Member**- Registered: 2013-07-12
- Posts: 13

I need to turn this linear equation 4x+11=6x-3 into a linear inequality.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,691

4x+11<6x-3 or 4x+11>6x-3 or 4x+11≤ 6x-3 or 4x+11 ≥ 6x-3

**In mathematics, you don't understand things. You just get used to them.**

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