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**{7/3}****Member**- Registered: 2013-02-11
- Posts: 210

I can't see any way to solve this

prove,a+bi=c+di implies a=b and c=d

There are 10 kinds of people in the world,people who understand binary and people who don't.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,820

That is not a true statement.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,731

I expect {7/3} meant

a = c and b = d

I think it is axiomatic rather than provable ... but as ever, it depends on the initial axioms chosen.

Bob

researching .....

LATER:

Looks like it isn't an axiom. hhmmm.

So try a-c = i(d-b) => i = (a-c)/d-b) =><= i is not real unless d = b

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,820

I do not think so.

a+bi=c+di

implies

a-c=(b-d)*i

If (b-d)!=0, then a-c is complex, which is not possible. So, b-d must be equal to 0, i.e. b must equal d. That further implies that a-c=0, i.e. a=c.

*Last edited by anonimnystefy (2013-07-01 20:06:17)*

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

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**{7/3}****Member**- Registered: 2013-02-11
- Posts: 210

thanks.

There are 10 kinds of people in the world,people who understand binary and people who don't.

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