Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2013-06-05 12:15:30

Au101
Member
Registered: 2010-12-01
Posts: 286

Rates of change (conical vessel)

Okay, so, having hopefully got myself re-acquainted with the very basics of differentiation, I now realise how much basic geometry I've forgotten tongue (sigh - if only i still had my formula books tongue). Anyway, enough complaining, so I'm looking at the chain rule and rates of change and the first question I have is:

So, does anyone know where I've gone wrong?

Last edited by Au101 (2013-06-05 12:16:11)

Online

#2 2013-06-05 18:47:38

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,528

Re: Rates of change (conical vessel)

hi Au101,

Welcome back; nice to hear from you again.  smile

I've read and re-read this problem and I cannot find anything wrong with your answer.  Maybe the book answer is just a typo.  It would be easy to type two 1s rather than two zeros.  My brain to finger coordination does this to me all the time.  With the answer expressed as a multiple of pi it's hard to see why 110 (not divisible be 4) would be correct.

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

Offline

#3 2013-06-05 19:38:18

{7/3}
Member
Registered: 2013-02-11
Posts: 210

Re: Rates of change (conical vessel)

I am confused,since (i) wants rate depending on depth.so we should calculate dv/dh at h=5(which is 25π).correct me if i'm wrong.

Last edited by {7/3} (2013-06-05 19:39:52)


There are 10 kinds of people in the world,people who understand binary and people who don't.

Offline

#4 2013-06-05 22:14:56

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,528

Re: Rates of change (conical vessel)

hi {7/3)

Rate is usually taken as wrt time. So asking for dV/dt

Also look at the units for the book answer.

This is what Au101 has done.

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

Offline

#5 2013-06-05 23:35:55

{7/3}
Member
Registered: 2013-02-11
Posts: 210

Re: Rates of change (conical vessel)

Ok.in that case shouldn't dV/dt be  a function in terms of t,not h?


There are 10 kinds of people in the world,people who understand binary and people who don't.

Offline

#6 2013-06-06 01:24:34

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,657

Re: Rates of change (conical vessel)

Well, h is a function of t, so it comes down to the same thing.


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

Offline

#7 2013-06-06 02:05:08

{7/3}
Member
Registered: 2013-02-11
Posts: 210

Re: Rates of change (conical vessel)

Thanks


There are 10 kinds of people in the world,people who understand binary and people who don't.

Offline

#8 2013-06-06 02:13:49

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,657

Re: Rates of change (conical vessel)

No problem.


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

Offline

#9 2013-06-06 02:57:19

Au101
Member
Registered: 2010-12-01
Posts: 286

Re: Rates of change (conical vessel)

It's great to be back, bob bundy smile Thanks so much. I have a feeling you're right, I just didn't have enough confidence in my answer, but the book agrees with me that the answer to part (ii) is:

{7/3} and anonimnystefy, you're absolutely right. We know that h varies with t, specifically, it varies at the uniform rate of:

(As the question tells us.)

And we know that V varies with h, specifically, it varies at a rate of:

(According to my calculations)

We know, then, that V also varies with t, since it varies with h, which varies with t. Specifically, by the chain rule, it varies at a rate of:

Online

#10 2013-06-06 07:43:02

Au101
Member
Registered: 2010-12-01
Posts: 286

Re: Rates of change (conical vessel)

Just a very very quick point of confusion I'd like to clear up, if I may: I have the question:

And after some mathematics, I come up with the solution that the length l of NT is:

Which agrees with the answer book, except the answer book does not have the modulus sign. I just wanted to clear-up why I can simply get rid of the modulus signs in this case, since my rustiness even extends to calculations of distance hmm tongue

Online

#11 2013-06-06 20:19:51

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,528

Re: Rates of change (conical vessel)

hi Au101,

Because it is measuring distance and that cannot be negative.  Without the || some values of t would give negative values for 4t^2 - 4t/3

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

Offline

#12 2013-06-06 23:58:43

Au101
Member
Registered: 2010-12-01
Posts: 286

Re: Rates of change (conical vessel)

So, surely, I should keep them? The answer book simply has

I had thought that maybe the answer book was giving a simplified answer, it's an old A-level book, but the syllabus was very different back then, so I'm never sure what I'm expected to know tongue But looking at it, if I draw a graph, I don't think T can ever - on this graph - be above N on the y-axis, so - presumably - the distance can always be given by N - T, with no need to worry about what would happen if T were to occur above N, giving a negative distance?

Online

#13 2013-06-07 00:34:51

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,528

Re: Rates of change (conical vessel)

Maybe it depends on the way a question is worded.  I've met some where the distance along the x axis  of a particle from the origin is given as a function of t.  For some t the distance comes out negative and you're supposed to interpret that as meaning the particle is to the left of (0,0) .

I doubt it would loose you marks either way.

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

Offline

#14 2013-06-07 00:40:03

Au101
Member
Registered: 2010-12-01
Posts: 286

Re: Rates of change (conical vessel)

Okay, thanks bob bundy smile I don't think I'll worry about it too much, I mean, I just want to get my calculus back to a good enough level to start looking at some new maths and physics &c., so it's just some general practice smile It's good for me to understand as much as possible though smile

Online

Board footer

Powered by FluxBB