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**ShivamS****Member**- Registered: 2011-02-07
- Posts: 3,463

Calculate the surface integral:

∫ ∫ with s on bottom. F dot dS where F (x,y,z) = = (2x + y + z ; x + 2y + z ; x + y + 2z)

where S is the surface of the box bounded by the planes x = 0, x = 1, y = 0, y = 4, z = 0, z = 5

I used the divergence theorem and got 120.

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**ShivamS****Member**- Registered: 2011-02-07
- Posts: 3,463

Some clarification

Calculate the surface integral seen there:

http://latex.codecogs.com/gif.latex?\int%20\int_{S}%20F\cdot%20d\mathbf{S}

when:

http://latex.codecogs.com/gif.latex?F(x,y,z)%20=%20(2x%20+%20y%20+%20z%20;%20x%20+%202y%20+%20z%20;%20x%20+%20y%20+%202z)

Thanks for bobbym for telling me about codecogs to make the stuff look better.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,072

Hi;

You can take codecog's output and put it between the math tags to create latex here.

Your answer of 120 by the divergence theorem is what I am getting. Hopefully, the conditions of that theorem have not been violated.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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