hi {7/3}
At points where the function is 'well-behaved', yes. eg. For your example, everywhere except x = 2.
At this point, it may still be ok. It is continuous there, so it passes that hurdle. You then need to consider whether there is a left limit for the chord gradient and a right limit, and whether they are the same.
So, whilst f(x) = 2x, the gradient function is 2, for all x.
Whilst f(x) = x^2, the gradient function is 2x, so the right limit, as x tends to 2, is 4.
So there is not a consistency between the gradient as x approaches 2 from the left, and the gradient as x approaches 2 from the right. So it is said that it is not differentiable at this point.
Bob