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#1 2013-05-22 22:29:43

barandaman
Guest

Rearranging Urgent Help!! Part 3, last one I promise!

tinypic.com/r/2u6gyef/5

Hi,
Could someone please help me with this problem?
I have done some of the deriving up to this point, so if we cannot move from the LHS to the RHS on the attached image, I have done something wrong up to this point and then I will take another photo to show the previous steps, but I really think they were right as it was much more simple.
So we have to get from the LHS to the RHS, dividing by ‘a’ gives the first two terms, but then I really do not understand how the LAST term on the RHS becomes ‘b/a’. Could anyone shed some insight? Thank you so much! Image attached.

#2 2013-05-22 22:57:16

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,636

Re: Rearranging Urgent Help!! Part 3, last one I promise!

Hi barandaman;

What have you done so far?


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#3 2013-05-22 23:02:00

barandaman
Guest

Re: Rearranging Urgent Help!! Part 3, last one I promise!

I will write it out neatly and take a photo because I have not learnt latex big_smile 5 minutes! big_smile

#4 2013-05-22 23:03:54

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,636

Re: Rearranging Urgent Help!! Part 3, last one I promise!

Hi;

See if you can write the problem out larger too.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#5 2013-05-22 23:09:09

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,391

Re: Rearranging Urgent Help!! Part 3, last one I promise!

hi barandaman

here's the LHS using Latex.

I think you need to do two things.

(i)  tell us what the question asks

(ii) show how you got this far.

Please use Latex:

You start with square brackets math and end with square brackets /math

The code for the above is:

 [math]a \pi^e = a \pi^{\Psi} + \frac{b(y^{ \Psi} - {ybar})}{a+b^2}[/math]

There is a code for the line over the y but I forget at the moment.  But ybar is clear I think.

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#6 2013-05-22 23:10:36

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,391

Re: Rearranging Urgent Help!! Part 3, last one I promise!

hi bobbym,

Didn't see your post as I was taking a long time over mine.  smile

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#7 2013-05-22 23:15:34

barandaman
Guest

Re: Rearranging Urgent Help!! Part 3, last one I promise!

tinypic.com/r/rgxlwy/5


It is the problem we looked at yesterday, to solve it we set PI=PI^e, so all that changes is the LHS term is PI^e.

Then I expand the RHS as seen, and get the result as shown initially in the first image. I have no idea how to convert that into the solution, which is:

Pi^e = Pi^* + (b/a)(y^* - ybar)

I hope this is clearer!

#8 2013-05-22 23:16:23

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,636

Re: Rearranging Urgent Help!! Part 3, last one I promise!

Hi bob bundy;

That is okay.

Use


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

Offline

#9 2013-05-23 00:44:22

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,391

Re: Rearranging Urgent Help!! Part 3, last one I promise!

hi barandaman

That last line is not quite correct.

Your pi terms have lost their denominator.

Put that in and you can cancel it throughout.  The expression is then much simpler.

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#10 2013-05-23 01:14:51

barandaman
Guest

Re: Rearranging Urgent Help!! Part 3, last one I promise!

bob bundy wrote:

hi barandaman

That last line is not quite correct.

Your pi terms have lost their denominator.

Put that in and you can cancel it throughout.  The expression is then much simpler.

Bob

I really am having trouble with the latex...

The pi terms are different, one is pi^e one is pi^*

#11 2013-05-23 01:21:07

barandaman
Guest

Re: Rearranging Urgent Help!! Part 3, last one I promise!

GOT IT! tghank you so much now i know what you mean, ahhhh thank you

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