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**mom****Member**- Registered: 2012-04-25
- Posts: 94

I am stumped again.

Find the equation of line L in standard form. L is parallel to y=1/3x.

I am not sure why I am thrown off. It shows line L with a point of (2,4)

I have y=-x+6 and I know that can't be correct because the slopw is 1/3 so is it y=-1/3x+6

I am really confused.

Please help to see what the answer is and why so that I can understand.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,861

hi Mom,

To be parallel it must have the same gradient, ie. 1/3

So y = (1/3)x + something..

(2,4) => 4 = (1/3)2 + something => something = 4 - 2/3

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,917

Well, we know that it must be of the form y=1/3 x+n, so we just substitute x=2 and y=4 and solve for n. Can you do that?

*Last edited by anonimnystefy (2013-05-08 06:59:03)*

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**mom****Member**- Registered: 2012-04-25
- Posts: 94

Im still lost but thanks Bob

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,861

http://www.mathsisfun.com/equation_of_line.html

and

http://www.mathsisfun.com/data/straight_line_graph.html

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**stapel****Member**- Registered: 2006-07-22
- Posts: 15

mom wrote:

Im still lost but thanks Bob

On which part are you lost? Thank you!

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**johnnie too lazy log in****Guest**

simple, just note that it goes thru (0,0), so subtract from y and and x the 2 and the 4.

(y-4) = (1/3)(x-2)

that's all there is to it.

very simple.

the end.

lol.

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