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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Oh, and please omit the "Mr". That makes me feel like I'm my dad!

"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Hi Bobby,

Yes, I had fun with that. I didn't know the iteration trick until the dice roll problem, but the thought sprang up in my mind and I came up with the trigger idea (B2*0 in cell B2) to utilize circular referencing. No doubt there's a proper way to do that, but mine worked and I haven't looked further.

The mathematics way I haven't got the first clue about...but, as you say, I'm sure it's a little nasty.

"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson

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**Raito****Member**- Registered: 2012-04-27
- Posts: 50

I am sorry,phrontister

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

Hi phrontister;

Good to see you. Your a clever guy even if you aren't a little person.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Hi Bobby,

Sorry to deflate your balloon (which all little people possess), but little people aren't at all clever. Wrong forum for this clue, I know...I'll copy it over to the right one.

Can't continue with that puzzle tonight, though, cos it's actually this morning...well, what's left of it!

"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

I know they are also doomed. Have a pleasant night.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Oh...I can't do that! "Topic closed". What now?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

Sorry, it is closed pending MIF's review of it. I can do nothing right now about that. Please hold on to the clue and post tomorrow.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Ok. G'night.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

Okay, see you later.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

In my posts #14 & #17 I've now included a direct link to a video of animated calculation results so you can see the effect of the iterations.

I increased column B's font size for a more vivid display...which slowed down the animations significantly.

*Last edited by phrontister (2012-04-28 05:55:29)*

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Hi Bobby,

Re the coin-flipping puzzle mentioned in post #17, could you please help me with my M code? I've done two versions of it, and version A works but version B's got a snag I haven't been able to fix.

Version A:

```
c = 0;
For[i = 0, i < 10000, i++,
If[StringCount[ToString[FromDigits[RandomInteger[1, 10]]], "1111"] > 0, c = c + 1]]; N[c/i*100 "%"]
```

Version B:

`N[Total[StringCount[Table[ToString[FromDigits[RandomInteger[1, 10]]], {10000}], "1111"]]/10000*100 "%"]`

The problem with version B is that it counts multiple occurrences of "1111" in an element: eg, "1111011110" scores 2 wins instead of 1, which incorrectly inflates the result.

Also, is there a function (something like StringCount) that can test the RandomInteger lists to see if they contain four consecutive elements that are all "1", so that I can eliminate "[ToString[FromDigits"? StringCount only works on strings (I think), and the only way I could get it to look at RandomInteger's lists was to convert the lists to numbers with FromDigits and then to strings with ToString...which seems to be two steps too many. But I couldn't find anything better (briefer).

Version A takes about 50% longer than version B.

*Last edited by phrontister (2013-05-02 21:19:11)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

This problem is also in another thread. I have not gone into it because the OP over there is not ready for a better idea. You unfortunately are.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,844

Yes, I saw that thread and I agree with you, which is why I posted here.

*Last edited by phrontister (2013-05-02 21:30:01)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

Are you attempting to solve this with a simulation?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

Have you tried using

`If[StringFreeQ[...,"1111"],0,1]`

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

The right way is not to simulate but to enumerate. I am getting 251 / 1024. The stupidity of the question is monumental! Why would they want to do a simulation of 10000 trials when there are only 1024 possibilities?

Try this:

```
s = Tuples[{0, 1}, 10];
(Cases[s, {___, 1, 1, 1, 1, ___}] // Length)/1024
```

B) Can be adjusted like this,

```
(Select[StringCount[
Table[ToString[FromDigits[RandomInteger[1, 10]]], {10000}],
"1111"], # > 0 &] // Length)/10000.
```

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

Instead of Cases[...]//Length you can just use Count[...].

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

Hi;

Yes, you can. the important thing is the difference in the method of solution. The enumeration gives the exact answer, something the simulation can never give.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

Yes, but if we wanted a simulation, phro's way is a good way to go.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

Not exactly, string operations are not necessary. It is more convenient to work with the preferred container of M. Lists!

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

I meant, in the sense of idea, bot in te sense of implementation.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

The first bit of code does run a good simulation.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

Here is my own code with no strings:

`Count[Table[RandomInteger[], {10000}, {10}], {___, 1, 1, 1, 1, ___}]/10000 // N`

*Last edited by anonimnystefy (2013-05-02 23:37:32)*

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,347

You will find this to be faster:

```
Count[Table[
RandomVariate[DiscreteUniformDistribution[{0, 1}],
10], {10000}], {___, 1, 1, 1, 1, ___}]
```

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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