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**praveenkesavan****Member**- Registered: 2013-05-02
- Posts: 2

I have a problem here with linear equations.

I got a set of straight lines whose slopes vary from 1 to 5 (linearly) and y-intercept vary from 0 to 100.

I have a point (x,y) whose slope is in between 1 and 5 and y-intercept is between 0 and 100. Is there any method to find the equation of line passing through (x,y) with which I can find y-intercept of that line?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 105,737

Hi;

I have a point (x,y) whose slope is in between 1 and 5 and y-intercept is between 0 and 100.

That is extremely vague and way too general. I need more to pin down the line.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

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**praveenkesavan****Member**- Registered: 2013-05-02
- Posts: 2

Hi,

I will explain the actual problem.

I am sensing liquid level whose measured value is affected by ambient temperature change. Sensor is calibrated for a particular temperature say (TC), but the measured value shows a deviation with a change in temperature. My aim is to find the error in measurement due to change in temperature and subtract it from measured value. For this purpose I measure both level as well temperature.

To observe the behavior w.r.t temperature I fixed the actual level constant and varied temperature for the range of interest and noted down the measured value at different temperature. It follows a linear variation for that level. I repeated the experiment at different levels and I found that the slope of the straight line is different. Slope decreases with an increase in level.

In real application, I will measure both level as well ambient temperature, from which I can calculate the difference in temperature from TC. I need to know what is the error caused by this change in temperature for that particular level. If the slope of above experiments are same then it is a straight forward calculation. But the slope also changes for different levels.

Hope the issue is clear.

What would be a practical solution for this problem?

Regards

Praveen K

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 105,737

Hi;

Practical solutions are done with numbers. All the other kaboobly doo called mathematics is not.

You have given me no data to work with. I am as powerless as a shark in the desert. A picture is worth a thousand words and a table of numbers is worth 1000 pictures.

Do you have actual measurements?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

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