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You are not logged in. #1 20060206 18:13:52
nonrequrent function for requrent fractal processesI'll try to explain one function. IPBLE: Increasing Performance By Lowering Expectations. #2 20060206 18:16:50
Re: nonrequrent function for requrent fractal processesAnd the other question: does IPBLE: Increasing Performance By Lowering Expectations. #3 20060206 19:54:24
Re: nonrequrent function for requrent fractal processesHere's a program in Mathematica: Code:str = "1"; in[2]:= Code:StringReplace[str,"2" > "34"]; StringReplace[%,"1" > "2"]; StringReplace[%,"3" > "1"]; p=StringReplace[%,"4" > "2"]; Print[p]; str=p; pt=Table[StringTake[p,{i}],{i,1,StringLength[p]}]; Print[N[Count[pt,"1"]/Count[pt,"2"],20]]; The first out gives the string, the second gives num(1)/num(2). IPBLE: Increasing Performance By Lowering Expectations. #4 20060206 19:55:45
Re: nonrequrent function for requrent fractal processesNow I'm starting with num(1)/num(2) question. IPBLE: Increasing Performance By Lowering Expectations. #5 20060206 20:45:05
Re: nonrequrent function for requrent fractal processesLim[row>oo] num(1)/num(2)=phi so , where x[[i]] means the ith element of list x. Last edited by krassi_holmz (20060206 20:46:43) IPBLE: Increasing Performance By Lowering Expectations. #6 20060207 04:48:01
Re: nonrequrent function for requrent fractal processesInteresting question, krazzi. I'm sure there must be a pattern hidden in there if we look hard enough. I'll have a closer look later, but for now I'll give you this formula, in case you don't know it: ...where is the n^{th} Fibonacci number. Why did the vector cross the road? It wanted to be normal. #7 20060207 06:35:08
Re: nonrequrent function for requrent fractal processesthank you, Mathsy, but I've known it. IPBLE: Increasing Performance By Lowering Expectations. #8 20060207 06:38:08
Re: nonrequrent function for requrent fractal processesThe fractal relation is that when we write the connections, we get a kind of tree. IPBLE: Increasing Performance By Lowering Expectations. 