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#1 2013-04-19 04:01:52

UrgentHelp
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Hey! Algebra question! Please help me!

Hi, I have spent SOOO long trying to manipulate this thing to get the right answer.. I really cannot do it.

Could you please help me? We have:

1/a = (2(1-u))/(((1-u)^2)-4g) + 2/(1+u)

#2 2013-04-19 04:02:57

UrgentHelp
Guest

Re: Hey! Algebra question! Please help me!

The Answer is:

a= (SQUAREROOT of 5-4b) - 2.

Please please help me! big_smile I really can not manipulate it to get this solution

#3 2013-04-19 04:09:17

bobbym
Administrator

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Re: Hey! Algebra question! Please help me!

Hi;

Where does the b come from?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#4 2013-04-19 04:13:48

bob bundy
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Re: Hey! Algebra question! Please help me!

hi Urgenthelp,

And where did u and g go?

Is this your expression?



Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

#5 2013-04-19 04:31:52

UrgentHelp
Guest

Re: Hey! Algebra question! Please help me!

Yes bob bundy, that is exactly it!

Bobbym, sorry that should =g, not b, really sorry.

I am getting so many notes but i cannot get that solution for u=...

#6 2013-04-19 04:38:12

UrgentHelp
Guest

Re: Hey! Algebra question! Please help me!

So to clarify the eventual solution is supposedly:

(SQUAREROOT of (5-4g)) - 2

#7 2013-04-19 04:45:47

bob bundy
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Re: Hey! Algebra question! Please help me!

hi Urgenthelp,

So we are getting closer.  But I still don't see where a has gone.  Is there another equation?  Where did this equation come from?

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

#8 2013-04-19 04:49:57

bob bundy
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Re: Hey! Algebra question! Please help me!

Another thought.  Could that 'a' be a nine ?

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

#9 2013-04-19 04:56:35

UrgentHelp
Guest

Re: Hey! Algebra question! Please help me!

bob bundy wrote:

Another thought.  Could that 'a' be a nine ?

Bob

I AM SO SORRY. I do not know why I cannot type, that a is meant to be 'u' just like the 'u' on the RHS.

The whole thing comes from differentiating, so u=(squareroot 5-4g) - 2

is the maximum for whatever g is. I am SO sorry for giving that typo and wasting your time. It is meant to be 1/u on the LHS too

#10 2013-04-19 05:32:56

bob bundy
Moderator

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Re: Hey! Algebra question! Please help me!

hi Urgenthelp

Got it.  Typing it up now.  I'll post every so often and then edit the post to add the latest bit.  That way I won't lose any of the bits (I hope)



multiply all terms by the common denominator to clear all fractions







collect all terms on the LHS



That's looks pretty nasty but I notice that putting u = 1 makes this expression zero => (u-1) is a factor



So one solution is u = 1 and I'll use the quadratic formula for the other two



The plus sign case is the one you want.  Presumably you can find a reason to disregard the other two.

smile

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

#11 2013-04-19 08:48:08

UrgentHelp
Guest

Re: Hey! Algebra question! Please help me!

This is the best post I have EVER seen. Thank you SOOO MUCH. You are incredible. I really don't know how you thought to take that route, it is brilliant. Really thank you! big_smile

#12 2013-04-19 18:04:59

bob bundy
Moderator

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Re: Hey! Algebra question! Please help me!

hi Urgenthelp,

Thanks for the nice reply!

I always try to avoid fractions in algebra, so the first step was to get rid of them.  Then I hoped that lots of factors would cancel, but no such luck.  So there was nothing to do but 'wade through' all that horrible algebra, hoping to avoid any slip ups.

When I got to the cubic I thought, "Oh no, that looks impossible"  But the answer you had posted suggested that the quadratic formula should be used.  So how to get to a quadratic?  Only by extracting an easy factor first. .... so I looked for one.  Tried u = 1 first (because it's the easiest) and it worked! smile   That encouraged me to think I was on the right lines and that I hadn't slipped up with the algebra so far.

The rest was routine, find the quadratic by examination, apply the formula, simplify.  Observe one answer is what you wanted.  Feel smug!  smile

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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