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**CoCoOster****Member**- Registered: 2006-01-29
- Posts: 11

Please help me. I am in dire need of assistance. I don't know how to change fractions such as 1/7 in a quadratic function. The problem is like this:

y= (-7x^2)+2x

The directions are as follows:

Complete these steps for a function.

a)Tell whether the graph of a function opens up or down.

b)Find the coordinates of the vertex.

c)Write an equation of the axis of symmetry.

For my equation of the axis of symmetry, I got:

-2/2(7)=-2/-14=-1/-7=1/7

Please explain the next step.

Do I round the decimal?

Do I leave 1/7 as a fraction?

HELP!!!!!!!!!!!!!

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**CoCoOster****Member**- Registered: 2006-01-29
- Posts: 11

Please help me. I'm desperate.

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**Ricky****Moderator**- Registered: 2005-12-04
- Posts: 3,791

Is it (-7)(x^2) or (-7x)^2?

"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."

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**kempos****Member**- Registered: 2006-01-07
- Posts: 77

if it's -7x^2 the function has a maximum (coordinates: (1/7; 1/7)

if its (-7x)^2 it wil have minimum

x= 1/7

you just leave it like this. i don't think you have to change it into decimal.

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**CoCoOster****Member**- Registered: 2006-01-29
- Posts: 11

thanks guys

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