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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

How?

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Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

Oh, that. I thought you meant that PSLQ can solve the problem from scratch.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,445

It can evaluate the integral, isn't that from scratch?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

The numerical integration evaluates it, and the PSLQ just finds a nice form. The PSLQ cannot get the answer on its own, so that is not fron scratch.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,445

The PSLQ finds the correct form using the basis vector you provide. It is correct inasmuch as it will agree to the digits you provide for that vector. The other method requires help from residues and equation solvers so it can not do it by itself either.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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It does do it on its own, because finding the residues is the part of tthe method. But solving the integral is not a part of the PSLQ.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,445

The roots of the equation are a separate process. And it requires an argand diagram.

You do not solve the integral, you get a numerical approximation.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

Getting the roots is still a part of the contour integration method. Numerical integration is not a part of the PSLQ.

Anyway, it's just semantics. We can just agree to disagree.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Does it matter whether or not what is part or what is not part? It is another method, that is what I am saying.

For instance, if I tell you that the integral we are now working on is equal to π / 3, how do you know that is correct? Are you going to trust the manipulations only?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

I can check in another way. What does that have to do with anything?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Yes but the PSLQ is still another method. I never said it was the only other method.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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But, it is not a method for solving the problem. It doesn't tell you all the steps necessary to do a problem. Contour integration method does.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,445

Is that a requirement for a method? Especially for a check? The steps of the program you typed in show you clearly the method.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

It depends on what you expect it to do. PSLQ is a method for turning approximations into exact anwers, but it is not a method for solvibg integrals.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
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I disagree, it is a method of proving an approximation is being well represented by a closed form to the the number of digits.

There is no known method for all integrals. As a matter of fact I believe the integral I showed you in that post was only done thanks to a PSLQ as are many others.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

bobbym wrote:

I disagree, it is a method of proving an approximation is being well represented by a closed form to the the number of digits.

Yes, that is true. But, as I said, it sai, it is not a method for solving integrals.

It might be a part of a method for solving integrals, but it itself is not a method for solving integrals.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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It refines numerical integration which is a method to get an integral.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

I do not see how that statement contradicts what I said in my last post.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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But as I said there are no cut and dry methods to solve an integral. More integrals can not be done than can be done by the standard methods. Numerical integration is a robust technique which theoretically can get a definite integral to any degree of precision. The PSLQ then determines whether that number has a simple relationship with the constants provided. Sounds like a method we all should be using and know.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

That still doesn't contradict what I said. Numerical integration+PSLQ is a method for evaluating integrals, PSLQ on its own is not a method for evaluating integrals.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,445

Neither is a contour. It requires, limits, derivatives and solving a tough polynomial.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

But it is! The solving of the equation, the limits and derivatives are all things that the method explicitly demands, and with all that is enough to solve an integral (not every though).

The PSLQ doesn't explicitly demand for numerical integration, and it itself is not enough to solve a problem.

Thos discussion is obviously pointless and I will not continue any further.

Here lies the reader who will never open this book. He is forever dead.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,445

Hi;

I am not angry at the discussion and you should not be either. If you do not want to discuss it anymore, I am okay with that. See you in the other thread.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

I am not angry. I am just tired of being misunderstood.

Here lies the reader who will never open this book. He is forever dead.

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