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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

Okay, Im here. And Bobbym, really haven't you ANY suggestions on how to begin these equations ? I'm feeling that there is no methodology in what Im doing...

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

It does take experience to do some of these. You gain that experience by doing them. The beginning stuff is right here:

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

Yes, I guess I'll still keep practicing. thanks

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

How about this one here:

Can you get c as the subject?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

c=b+2/a

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

That is correct!

Make b the subject.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

Just a question, If I distribute the b on the right, I must also distribute it for 2 ? (Must I distribute to all the right side of the equation ?

1/a=2b ?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

Hi;

I am not following you. What are you trying to do?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

Im trying to isolate b on the right of the equation, but must I also distribute the B to the whole right side of the equation ?

*b 1/a=1/b+2 *b (to the 1/b AND to the 2)

which gives :

b/a=2b

?

*Last edited by Al-Allo (2013-03-10 07:15:06)*

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

Foget my question, heres my answer b=2a

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

Hi;

That is not correct. Please show me your first step.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

*b 1/a= 1b +2 *b

b/a=+2

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

The left side is correct.

When you multiply the right side by b, that means everything on the right gets multiplied by b. Try it again.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 290

Sorry Bobbym, Ive got other to finish. Il try it on my own, Im feelng that Im lacking knowledge in algebra, maybe I should do a review ^^

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,654

You only need some practice on that type.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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