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**∞****Guest**

I was just curious, what is the formula for the surface area and volume,

and respectively, for a pyramidal frustum and a conical frustum? I would prefer you to put it in LaTeX so I can easily understand it. Thanks!Note: later I may ask for other formulas, so don't put away your brain when you're done!

**∞****Guest**

Oops, I almost forgot; I would also like a picture showing where the demensions are. Thanks...again!

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,362

Hi;

For a right pyramidal frustum:

Look here for more:

http://mathworld.wolfram.com/PyramidalFrustum.html

*Last edited by bobbym (2013-03-06 21:11:26)*

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**∞****Guest**

Thanks!

I do want to ask though, is a right frustum just a straight, generic one? Or is it one that is tilted?

Also, I checked out the link, and it seems that the full surface area (as in, the whole surface of it including bases) is:

Am I right? I am kind of confused. The volume formula though, is easy for me to understand.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,362

Hi;

It is much better to write it like this:

check out this url:

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**∞****Guest**

Sorry I wrote that wrong.

Thanks, again; I think I now understand it. (:

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,362

Hi;

Okay, you are welcome.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**∞****Guest**

Next geometry question I've been wondering:

What is the perimeter

I was thinking it was where is the larger radius, but what about the inner part?

Is that included in the formla, or is it just the 'strict' outside?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,362

Hi;

The perimeter of an annulus is the sum of the perimeter of the two circles, interior and exterior.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**∞****Guest**

6 more (these might be tougher than before):

1. A & P of a Lune of Hippocrates.

2. V & S of spherical cap.

3. V & S of a spherical sector.

4. V & S of a spherical segment.

5. V & S of a spherical shell.

6. V & S of a spherical wedge.

Where V = volume, S = surface area, A = area, P = perimeter.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,362

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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