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You are not logged in. #1 20130228 04:34:22
Quadratic EquationFind the condition that the roots of the equation are in the ratioMy problem is that I didnt understood this question i.e.. the language ,what condition its talking about... the two roots may be ma and na that will be in the ratio but what I have to show/do here. Thanks:) Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #2 20130228 06:03:07
Re: Quadratic EquationHi; with r1 being an arbitrary root. Last edited by bobbym (20130228 06:03:44) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20130228 11:19:00
Re: Quadratic Equation
Let the roots be and . Thus
Eliminating gives as the required condition. Test: have roots in the ratio . Last edited by scientia (20130228 11:24:16) #4 20130301 03:06:12
Re: Quadratic EquationOk I think you guys didn't understood what I was asking for... Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #5 20130301 03:10:39
Re: Quadratic EquationHi; Last edited by bobbym (20130301 03:12:51) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #6 20130301 03:19:15
Re: Quadratic Equation
I have seen that... But still I am confused... I think I have to think about some more time... Thanks Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #7 20130301 03:26:33
Re: Quadratic EquationHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #8 20130301 03:56:16
Re: Quadratic EquationI had also never seen this kind of stuff earlier... Solution : Let and be the two roots of the equation Now, Eq 1 and Eq 2 From Eq 1 we have , or , or ,  By Eq2 or , which is the required condition Last edited by debjit625 (20130301 04:09:08) Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #9 20130301 05:28:56
Re: Quadratic EquationWhat the bleep is wrong? The question asks for the condition under which certain things hold. I worked out and gave the condition. Just what are you not happy with?
Look. You asked a question. I took the time to help you with it. It was late, I could have gone to bed, but I stayed up to help you. Is this the gratitude I get in return? #10 20130301 07:02:18
Re: Quadratic EquationHi scientia; Last edited by bobbym (20130301 07:05:07) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #11 20130301 18:03:44
Re: Quadratic Equation
scientia ,if you can read English and understand it then look at post #4 ,I appreciated your work ,I thanked you...
Yes, in general I speak English and understand it properly, but this question is not very much clear and I think bobbym also agreed with me on #7 And you just solve the equation ,that what you did in my case ,will not answer his/her question, you need to explain him/her what does the roots means in an quadratic equation. You knew what I asked for... but you yourself don’t understand the question clearly, posting the solution doesn’t means you know about it, their are many books where you will find this question and its solution. Now the main thing, please please please please never ever try to help me again in future ,just stick with your bed and have good dreams... Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #12 20130301 19:53:53
Re: Quadratic EquationHi; Last edited by bobbym (20130301 21:13:38) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #13 20130302 01:42:41
Re: Quadratic EquationDebjit, are you a bengali? 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #14 20130302 07:18:52
Re: Quadratic Equationdebjit625, I'm sorry for my badtempered post above. I suppose I had had a bad day and somehow let it spill over onto the forum. It was totally wrong of me and I apologize. Anyway, "condition" simply means something that has to be fulfilled in order for a given statement to be true. For example, suppose the question was: "What's the condition under which the quadratic equation , , has no real roots?" Then the condition would be: . In order for the statement ", , has no real roots" to be true, the condition has to be fulfilled. In this particular question, the statement is " () has roots in the ratio ". In order for this to be true, we must have . This is the condition that has to be fulfilled in order for the given statement to be true. Last edited by scientia (20130302 07:20:03) #15 20130302 20:35:36
Re: Quadratic Equation@scientia I am sorry too, for being so rude Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #16 20130302 21:48:10
Re: Quadratic Equation'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda 