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**RickyOswaldIOW****Member**- Registered: 2005-11-18
- Posts: 212

I have a question here that asks to explain the transformations and sketch the graph of

y=4/x

I know that on a graph of y=x² you can put y=x²+z and the curve will be moved along the y axis by z. y = (x+z)² will move it along the x axis by z (but with a reversed sign). Similarly y=2x² will double each y co-ordinate; *How would I write it so that each x co-ord is doubled?*

Also, back to my original question on the curve of y = 1/x, if y = -1/x rotates the curve in the x-axis, why is y = 4/x supposedly scaling in the y-direction?

*Last edited by rickyoswaldiow (2006-01-24 01:47:33)*

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

To enlarge the x co-ordinates of a function f(x), you need to change the function to f(ax), where 1/a is the amount that you want to enlarge it by.

So, to multiply all the x co-ordinates in y=x:sup2 by 2, you would have to change it to y=(x/2):sup2 = x:sup2/4.

And changing y = 1/x *does* scale it in the y direction, it just happens to scale in in the x direction as well because of symmetry.

Why did the vector cross the road?

It wanted to be normal.

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**RickyOswaldIOW****Member**- Registered: 2005-11-18
- Posts: 212

so y=2x² doubles each y co-ord and since y=1/2x² halfs each, that has the same effect as doubling each x co-ord?

With a curve of y=1/x, it gets scaled in both directions when the integer(1) there changes?

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**God****Member**- Registered: 2005-08-25
- Posts: 59

Picture y = -1/x as scaling the curve by a scale factor of -1.

The fact that you can also rotate the curve to get -1/x is a sidenote.

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**RickyOswaldIOW****Member**- Registered: 2005-11-18
- Posts: 212

y = -1/x rotates the curve in the x-axis

and

y = 4/x scales in the y-direction

are the "correct" answers shown in my a-level book. I don't see why they switch between y and x axis?

Aloha Nui means Goodbye.

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