Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2006-01-21 09:11:27

katy
Member
Registered: 2005-12-28
Posts: 14

Can anyone show me how to graph this please...

How can you change this to descriptive form, graph it and state the Domain, HA(Asymptote), Y-intercept and X-intercept??Please give me a tutorial!

y=(3x+2)/(x+1)


thanks a lot.....:o

Offline

#2 2006-01-21 09:24:51

irspow
Member
Registered: 2005-11-24
Posts: 1,055

Re: Can anyone show me how to graph this please...

The x-intercept occurs when y = 0;

0 = (3x+2)/(x+1);

This is only true when 3x+2=0 or x = -2/3

  Similarly the y-intercept occurs when x = 0;

(3x+2)/(x+1) when x = 0 becomes 2/1 or 2

A horizontal asymptote occurs when the functions has a limit as x approaches infinity.

If you divide the numerator and the denominator by the highest power of x in this question you get;

y = (3 + 2/x) / (1 + 1/x)

if you let x approach infinity then;

y = 3/1 or 3


I am at an age where I have forgotten more than I remember, but I still pretend to know it all.

Offline

#3 2006-01-21 09:34:13

irspow
Member
Registered: 2005-11-24
Posts: 1,055

Re: Can anyone show me how to graph this please...

Sorry, I forgot about the domain.

The domain is the range of values of x that give a real value of y.

The only time this function would not do so is when the denominator was zero, because division by zero is not allowed.

This only happens when x = -1;

So the range would be -∞≤x<-1, -1<x≤∞


I am at an age where I have forgotten more than I remember, but I still pretend to know it all.

Offline

#4 2006-01-21 09:55:47

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Can anyone show me how to graph this please...

I'd have just said x∈R, x≠-1. But everything's still right though. Well done.


Why did the vector cross the road?
It wanted to be normal.

Offline

Board footer

Powered by FluxBB