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You are not logged in. #2 20060120 18:17:35
Re: it looks easy but ...doesn't look easy at all. Absolute value algebra is a nightmare! A logarithm is just a misspelled algorithm. #3 20060120 18:26:19
Re: it looks easy but ...incase your not sure where I got the requirements from. If you have an expression such as x + 1 if the value of x + 1 is less then zero, it will be negative. Therefore, if x + 1 is less then 1, the expression will haves its sign changed. Thus x + 1 equals (x + 1) when the expression is less then 1. To find when x + 1 is less then zero: x + 1 < 0 solved x < 1. Lets try a value less then 1 as a test. 2 + 1 = 1. But 2 is less then 1 so instead of  x + 1 we can write ( x + 1) x = 2 so A logarithm is just a misspelled algorithm. 