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#1 2013-01-25 07:23:56
- White_Owl
- Full Member
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integrate x/sqrt(3x+25)
In my homework for this week I have a question:
If I do a substitution u=3x+25, then I have
Which does not help much.
If I try to find such u that du will eliminate x from numerator, then: du=1/x dx and u have to be ln(x)
Which is also not very helpful...
Finally I run the original integral through Maxima, and it gave me:
Which is very scary and I have no idea how it come to this formula.
So which "u" should I use? How to find such "u"? Or maybe there is another approach I should use? I am completely stuck.
#2 2013-01-25 07:42:10
- anonimnystefy
- Real Member
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Re: integrate x/sqrt(3x+25)
Hi White_Owl
Continuing on the first thing you tried:
Can you continue from here?
Last edited by anonimnystefy (2013-01-25 07:49:57)
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#4 2013-01-25 09:55:19
- anonimnystefy
- Real Member
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Re: integrate x/sqrt(3x+25)
Hi White_Owl
You have multiplied by 3 instead of dividing by 3 when making the substitution...
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#6 2013-01-26 13:30:01
- anonimnystefy
- Real Member
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Re: integrate x/sqrt(3x+25)
You're welcome! 
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón