Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**skylor b****Guest**

express the edge length of a cube as a function of the cubes diagonal length d. then express the surface area and volume of the cube as a function of the diagonal length.

1. a function for the edge length of cube is l(d)=?

2. a function for the surface area of a cube is a(d)=?

3.a function for the volume of a cube is v(d)=?

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

skylor: You keep posting questions and then give no response to what I'm offering.

Are my posts helpful?

Can you do the problems you have previously posted ?

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

yes they are thank you

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

OK. So let's do one at a time, shall we.

How would you work out the length of the diagonal of a cube if the side has length x ?

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

x^3?

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

That cannot be right. You are calculating a distance so it should not have a cube term in it.

Take a look at my cube picture below. (I did this for someone else who posted a problem earlier)

You want the length of AG in terms of AB = x

Use Pythagoras to work out EG in triangle EGH.

Then AG in triangle AEG.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

ok but im confused because there are no numbers. am I just supposed to give the forumula

**skylor****Guest**

so itd be

l(d) =sqrt(3d)

a(d) = 6s^2

v(d)= d^3

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

hi skylor

am I just supposed to give the forumula

Yes.

l(d) =sqrt(3d)

a(d) = 6s^2

v(d)= d^3

Now you are getting closer.

d is for the diagonal. I'm using x for the side.

So the first should be

So now re-arrange this to get x in terms of d. That will be the formula l(d) for Q1.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

I think it should be sqrt (3x)

**skylor****Guest**

I think I have this one down thank you

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

I think it should be sqrt (3x)

I disagree.

You calculated like this:

So

There is a 'theory' in physics that covers the 'dimensions' in formulas.

In this case it says

You cannot have

I suggest you post your other answers for these questions so I can check them.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

these are the formulas I am using

l(d) =sqrt(3d)

a(d) = 6s^2

v(d)= d^3

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

I have seen these already.

I don't think any are correct.

I am trying to lead you through like this.

(i) get the correct formula for d in terms of x.

(ii) re-arrange it to get x in terms of d

(iii) get the correct formula for the surface area in terms of x

(iv) use (ii) to write the surface area in terms of d

(v) get the correct formula for the volume in terms of x

(vi) use (ii) to write the volume in terms of d.

So far I have told you (i) and you haven't got (ii) right.

And you have posted yet another question.

What is the point of this when this question is not yet done?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

I replaced x with d in those problems. Is that what was wrong?

I posted another question because it is confusing me and I feel like I understand this one enough for class now.

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

I replaced x with d in those problems. Is that what was wrong?

Yes. Let's say that x = 5. Then d = √3 times 5 = 8.66,,,,

So given that d = 8.66,,,, how do you calculate x ?

So what is the formula for x in terms of d ?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

take the sqrt of that?

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

√8.66 = 2.94....

You should be saying how to get the answer 5.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

hm ok thanks. I think if I know the formula I should be ok.

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

So what do you think it is?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**skylor****Guest**

3.87

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,054

That isn't a formula.

x = something with a d in it.

B

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

Pages: **1**