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#1 2013-01-18 21:13:03
- kjames
- Guest
mixture problem
HELP!!!
A 90% KCN solution is diluted with water to make a solution of 60% acid. When 3 gallons of water is added to dilute it again, the solution becomes 40% acid.
a. how much water was added to the solution on the first instance?
b. what was the original volume of the 90% acid solution?
#2 2013-01-18 22:00:19
- bobbym
- Administrator
Online
Re: mixture problem
Hi;
K = the amount of KCN
w = the amount of water
a = amount of water added
K = 2 / 5
w = 18 / 5
a = 2
You should be able to answer a and b now.
By the way, KCN is the salt of a strong base KOH and a weak acid HCN therefore is it a base not an acid.
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