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You are not logged in. #1 20130104 12:25:11
linesSuppose you graphed every single point of the form . For example, when have, we have and so is on the graph. Explain why the graph is a line, and find an equation whose graph is this line.Last edited by cooljackiec (20130104 12:26:24) I see you have graph paper. You must be plotting something #2 20130104 14:11:18
Re: linesHi;
(2 t + 3, 3  3 t) substitute in the second equation y = 3  3 t That is the equation of the line and it also answers the first part of the question. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20130105 11:05:53
Re: linesFind the sum of all values of a such that the point (a,7) is from the point (2,1).Last edited by cooljackiec (20130105 11:08:39) I see you have graph paper. You must be plotting something #4 20130105 11:39:01
Re: linesHi That is the equation of the circle that represents all the points that are 3√(5) from (2,1) You want the intersection of y = 7 with that circle. x = 1 and x = 5, so a = 1 and 5. Add them up and get 4. See the drawing below. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20130105 12:51:33
Re: linesThanks. Nice profile pic I see you have graph paper. You must be plotting something #6 20130105 12:53:19
Re: linesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #7 20130106 04:40:22
Re: linesfind all x where . Interval notation?I see you have graph paper. You must be plotting something #8 20130106 06:03:25
Re: linesTreat it like an equation except replace the = sign with a ≤ sign. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #9 20130108 11:20:17
Re: linesI don't get when to use ( and ] I see you have graph paper. You must be plotting something #10 20130108 18:55:14
Re: lineshi cooljackiec You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #11 20130109 11:59:36
Re: linesI have a large truck and my neighbor has four identical small trucks. My truck can carry at least 800 pounds more than each of her trucks, but no more than onethird what all four of her trucks combined can carry. Knowing only these facts, what is the largest number of pounds that I can be assured of being able to carry in my truck? I see you have graph paper. You must be plotting something #12 20130109 15:59:34
Re: linesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #13 20130110 15:33:00
Re: lines:cool::DYou are correct I see you have graph paper. You must be plotting something #14 20130110 15:47:40
Re: linesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #15 20130111 12:07:34
Re: linesAnyways, i have a new problem: 2) Find BA if the graph of Ax + By = 7 passes through (2,1) and is parallel to the graph of 2x  7y = 3 3)The "perpendicular bisector" of the line segment is the line that passes through the midpoint of and is perpendicular to . The equation of the perpendicular bisector of the line segment joining the points (1,2) and (5,12) is y=mx+b. Find m + b. I see you have graph paper. You must be plotting something #16 20130111 12:18:56
Re: linesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #17 20130111 12:37:09
Re: linesI am still unsure about 2) and 3) I see you have graph paper. You must be plotting something #18 20130111 12:38:18
Re: linesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #19 20130111 12:39:48
Re: linesI think 3) is wrong, could you express it in slope intercept? I see you have graph paper. You must be plotting something #20 20130111 12:45:51
Re: linesHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #21 20130111 13:15:26
Re: linesnever mind, i understand it I see you have graph paper. You must be plotting something #22 20130111 13:17:34
Re: linesOkay, but call out if you need help. Sorry for the typo. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #24 20130113 23:49:17
Re: linesHi; the equation of the circle with center at (4 , 1) is Solve them both simultaneously: In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 