Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20130104 23:59:28
challenging problem for all5 rays are drawn from a point in space such that angle between any two rays is equal then find that angle? #2 20130105 00:15:39
Re: challenging problem for allhi rajinikanth0602 You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #4 20130105 01:54:46
Re: challenging problem for allI would say 72°. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #5 20130105 11:56:49
Re: challenging problem for allIt would be 72° if all the rays were in the same plane. Judging from the word "challenging" in the thread title, I'd assume the OP wanted the rays to be spread out in 3D space. #6 20130105 12:43:17
Re: challenging problem for allThen it seems it is not possible... I might be wrong though... The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #7 20130105 13:53:07
Re: challenging problem for all
Hi Rajnikanth, Hope you have seen a lot of Tamil Films. Are the angles on the same plane? Or did you mean any adjacent? 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #8 20130105 19:49:44
Re: challenging problem for allI assumed that these rays are in 3D space with every ray at the same angle to the other 4. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #9 20130105 22:58:48
Re: challenging problem for allHi Bob The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #10 20130106 00:52:48
Re: challenging problem for allhi Stefy, You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #11 20130106 01:17:07
Re: challenging problem for allHey Moderators, 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #12 20130106 01:21:24
Re: challenging problem for allThat depends on what you say. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #13 20130106 02:27:48
Re: challenging problem for allConjecture: In a plane(or a 2D space), you cannot have more than two rays from a point such that all the angles so formed are equal. Similarly, in a 3D space you cannot have more than four rays with such a property 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #14 20130106 02:50:20
Re: challenging problem for allHi Bob The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #15 20130106 02:54:35
Re: challenging problem for allOne more thing I must say, 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #17 20130106 08:51:35
Re: challenging problem for allHi Bob The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #18 20130106 20:25:00
Re: challenging problem for allhi Stefy,
I reread the question. So all five come from one point. proving impossibility has suddenly got easier. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #19 20130107 01:36:56
Re: challenging problem for allThanks for the proof 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda 