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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4508 and #4509 are correct. Brilliant!

Given sec θ = 13/12, find

#4510. cosec θ

#4511. cot θ

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4510 and #4511 are correct. Good work!

In triangle ABC, right angled at B, if

, find the value of#4512. sin A cos C + cos A sin C

#4513. cos A cos C - sin A sin C

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4512 and #4513 are correct. Neat work!

#4514. In a triangle ABC right angled at C, if tan A =

, find sin A cos B + cos A sin B.#4515. If cosec A = 2, find the value of

.Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4514 and #4515 are correct. Neat work!

Evaluate :

#4516. sin 60[sup]o[/sup] cos 30[sup]o[/sup] + sin 30[sup]o[/sup] cos 60[sup]o[/sup]

#4517. 2 tan[sup]2[/sup]45[sup]o[/sup] + cos[sup]2[/sup]30[sup]o[/sup] - sin[sup]2[/sup]60[sup]o[/sup]

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4516 and #4517 are correct. Good work!

#4518. If tan θ =

, then find the value of sin θ.#4519. If sin θ = 5/13, then find the value of tan θ.

Character is who you are when no one is looking.

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**scientia****Member**- Registered: 2009-11-13
- Posts: 222

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi scientia and bobbym,

The solutions #4518 and #4519 are correct. Good work!

#4520. Find the value of cosec[sup]2[/sup]55[sup]o[/sup] - cot[sup]2[/sup]55[sup]o[/sup].

#4521. If cot A = 20/21, find the value of cosec A.

Character is who you are when no one is looking.

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**scientia****Member**- Registered: 2009-11-13
- Posts: 222

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi scientia and bobbym,

The solutions #4520 and #4521 are correct. Good work!

#4522. If cosec θ = 41/40, find the value of cos θ.

#4523. If cos θ = 3/5, find the value of (sin θ - cot θ)/2 tan θ.

Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi,

#4524. If tan θ = 4/3, find the value of (3sinθ + 2cosθ)/(3sinθ - 2cosθ).

#4525. If cot θ = b/a, find the value of (cos θ + sin θ)/(cos θ - sin θ).

Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi,

#4526. If

, find the value of#4527.

= ?Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**scientia****Member**- Registered: 2009-11-13
- Posts: 222

*Last edited by scientia (2013-01-06 05:46:33)*

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi,

bobbym : The solutions #4524, #4525, #4526, and #4527 are all correct. Outstanding!

scientia : The solution #4527 is correct. Excellent!

#4528.

#4529.

= ?Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4528 and #4529 are correct. Excellent!

#4530. Find the value of

.#4531. Find the value of

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 12,946

Hi bobbym,

The solutions #4530 and #4531 are correct. Neat work!

#4532. Find the value of

.#4533.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,622

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline